X^2-5x-546=0

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Solution for X^2-5x-546=0 equation: 



X^2-5X-546=0

a = 1; b = -5; c = -546;
Δ = b2-4ac
Δ = -52-4·1·(-546)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$


$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-47}{2*1}=\frac{-42}{2}
=-21
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+47}{2*1}=\frac{52}{2}
=26
$

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